Answer / petee

fools! when someone has already explained (correctly) how to do it in only 7 races, how can you come in with answers like 11, 12, 13?? lol absurd!

Answer / surya

7 race is enough.. conduct 5 race in each race we can eliminate last two since we need only 3 horses. then conduct 1 race fa the toppers of each race, in this race eliminate the last 2 and also its group.the 1st of this race is the fastest.. den we ll have only 5 horse left conduct a race fa dem and find the nxt two horses. as simple as that.

Answer / soundararajan krishnan

Hi All,
The Answer is 11.
25 horses can be diveded into 5 batch and we can select
best 15 horses.

Here we are looking for best 3 from 25. So in each batch
the horse placed 4th and 5th place cannot beat the 1st
three placed horses in their batch. So we can dis qualify
them.

Note: race count=5

Now the 15 horses can be divided into 3 batches and can
select best 9 among them.

Note: race count = 5 + 3 = 8

These 9 can be divided into two batches. 5 in 1st batch and
4 in 2nd batch.

1st batch 5 horses result
1(Qualify for final)
2(Qualify for final)
3(include in 2nd batch for next race)
4(disqualify)
5(disqualify)

Note: race count = 5+3+1 = 9

2nd batch 4 horses + 1st batch 3rd place horse result.
1(Qualify for final)
2(Qualify for final)
3(Qualify for final)
4(disqualify)
5(disqualify)

Note: race count = 5+3+1+1 = 10

Now there are 5 horses qualified for final.
Among these 5 we can select best 3 horses.

Note: Total race count = 5+3+1+1+1 = 11.

If any doubt in my explanation please reply..

Answer / sravya geethika

my answer is 12

first best 15 horses from 5races
next bes 9 horses from 3 races
next best 6 horses from 2 races
here evry one made a mistake one race
is held because there cant be a race with one horse
and final race btn final 4

5+3+2+1+1=12

Answer / gaurav

One confusion if 6 then five races for top five and then
one to find top three but how could u decide that
first ,second third of first race is not the top three as
it may happen third of first race can fatser than first of
rest races we have to consider top three from each race.

Answer / alphy

My ans is 12. I will explain with a diagram

5 5 5 5 5 -> now 5 races each with 5 horses
| | | | |
3 3 3 3 3-> selected 3 toppers from each race so tot 15
horses remaining
5 5 5-> now again 3 more races ie tot 8 races yet
| | |
3 3 3-> selected 3 toppers from each race so tot 9
horses remaining
5 4-> now again 2 more races ie tot 10 races yet
| |
3 3 selected 3 toppers from each race so tot 6
horses remaining
5 _> one more race tot 11 races
|
3 + 1

4 _> one more race tot 12 races
|
3

So tot no of races 12.

But here we assume tht two horses never reach the
destination at the same time :-) if we consider that then no
of races will be much more.

Answer / madhu balaji

first five races,
5 5 5 5 5
| | | | |
3 3 3 3 3 total horses remaining=15

take the top one from five races
now you can select the best horse by keeping one
race.take second and third position horse from that race
and neglect forth and fifth.
keep two races for other two batches and select the top
two horses.
[total race: 5+1+2, remaining horses: 2+2+2 and the best is
selected]
now aim is to select second and third.
keep race for 5 horses and select top 2 and make it to
race with the one remaining.now you can select the second
and third best.
thus total race=5+1(selecting the best)+[(2+2)->for
selecting second and third]
TOTAL RACE: 10
(if you want to convey anything,you can mail me)

Answer / alok chandra

Could you please explain me how you got 6 as your answer. I
could do it in a minimum of 11 races. There has to be
atleast 5 races to select 15 horses. The 15 horses then
compete among themselves and best 9 horses are chosen. The
9 horses then run in groups of 5 and 4. From the group of
5, three horses are selected. The horse which comes third
is made to run in the next group as well. We again choose
three horses from the group. So that makes it a group of 5
fastest horses. Then run the last race by which we can
determine the three fastest horses.

Answer / ramz

6 Races

First Five Races

3+3+3+3+3=15 (first three winners from each race)

6th, 7th & 8th Races are 1+1+1=3 (first winner from each
race)

Answer / edward mohan

After 5 races-->we will have top 15 horses
+ After 3 races-->we will have top 9 horses
+ after 2 races--> we will have top 6 horses

Conduct 1 race for any 5 horses and select the best three.

make the remaining one horse run with those three
(after 1 race for 4 Horses --> top 3 horses)


Total races = 12

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