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1/3 rd of the contents of a container evaporated on the 1st
day. 3/4th of the remaining contents of the container
evaporated on the second day.
What part of the contents of the container is left at the
end of the second day?
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Assume that contents of the container is X
On the first day 1/3rd is evaporated.
(1 - 1/3) of X is remaining i.e. (2/3)X
On the Second day 3/4th is evaporated. Hence,
(1- 3/4) of (2/3)X is remaining
i.e. (1/4)(2/3)X = (1/6) X
Hence 1/6th of the contents of the container is remaining
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