given the following:
77 A PIC 9V9 VALUE 9.5
77 B PIC 9 VALUE 9.
77 C PIC V9 VALUE 0.8
77 D PIC 9
77 E PIC 9
77 F PIC 9V999
what are the contenta of D E nad F after the following
statements are
executed:
COMPUTE F ROUNDED=A+C/B
MULTIPLY A BY C GIVING E
ADD B C A GIVING D ROUNDED
a.F=9.589 E=8 D=1
b.F=9.589 E=8 D=9
c.F=9.589 E=7 D=9
d.F=9.589 E=7 D=1
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Answer / ram g [mind tree]
c is the correct answer ...
the result will be like this
f = 9589
e = 7
d = 9
bcoz num truncation will happen in left.
for eg: if you try to store 123 in 01 x pic 9.
the value of x should 3 not 1.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / amaranatha reddy
this is AMAR(amaran.akg@gmail.com)9043264468
the correct ans: " C "
we 've 4 options, in that no need to check "f" value
next,about "E"
E pic 9(1)
A*C=E
9.5*0.8=7.6[9(1)=7]
hence E=7
now we go C&D for our solution
about "D":
---------
D=B+C+A=9+0.8+9.5=19.3
according to question
"D" i rounded
as per our answer data trunk-ed occur
for numeric literals data assigning is from right to left
-------------
(for integer positions)&left to right(for decimal positions)
------------------------------------------------------------
so Value of "D"=9
--------
hence solution is\ ""C"" \
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| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ulhas
Its 100 % 'd' only.
Third statement 'ADD B C A GIVING D ROUNDED' gives
19.3 but as D is declared as pic 9. it will have only 1.
| Is This Answer Correct ? | 1 Yes | 5 No |
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