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consider the following piece of code
01 GROUP-ITEM
05 AMOUNT-1 PIC 99V9 USAGE COMP VALUE 50
05 AMOUNT-2 PIC 9(4)V99 USAGE COMP
MOVE ZERO TO GROUP-ITEM
ADD 50 TO AMOUNT-1
what will be the content of AMOUNT-1?
a.50
b.100
c.0
d.unpredictable
- 10 Answers
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Answer / suresh
hi naveen,
Actually we are moving 0 to group-item so it will become
zero and adding 50 to amount-1. Hence Amount-1 is 50.
please correct me if i am wrong.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / man
d. unpredictable
GROUP-ITEM is considered as alphanumeric. You can only
initialise a group item.
| Is This Answer Correct ? | 3 Yes | 1 No |
Ans is D and this 100% proof i have tested
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / priyanka
IDENTIFICATION DIVISION.
PROGRAM-ID. HELLO.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 GROUP-ITEM.
05 AMOUNT-1 PIC 99V9 COMP USAGE COMP VALUE 50.
05 AMOUNT-2 PIC 9(4)V99 USAGE COMP.
PROCEDURE DIVISION.
A000-FIRST-PARA.
INITIALIZE GROUP-ITEM.
MOVE 0 TO GROUP-ITEM.
ADD 50 TO AMOUNT-1.
DISPLAY AMOUNT-1
.
STOP RUN.
If we don't use " MOVE 0 TO GROUP-ITEM." condition then the answer is 50 else if we are using it then the answer is 32.0. so I think the right answer is unpredictable.
Please correct in email if I am wrong.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / harish
u r right a. 50
pls correct me if anything wrong
HARISH POOMGAME SHIVAPPA(hassan,karnataka)
NIIT TECHNOLOGY
KOLKATA
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / sachin borase
yes answer will be 50.
But if you initialize instead of move zeros then
value will be 100.
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / naveen
Why not C?
Can we have the reason for the above answer?
| Is This Answer Correct ? | 0 Yes | 2 No |
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