Answer / marcedward

8 races.
Race Set A = 5x5 to rank top 5 leaders
Race B = top 5 from each group race each other winner is #1 Fast horse
Race C = 2nd place from Race B races with the other horses that were within #1's group in Race A(the only horses who could be faster) winner of that race is #2 Fast Horse
Race D = 2nd place from race C races 3rd place from race B, you have 3rd fastest horse.

Answer / nikky

This question cannot be answered as it is given tthat a
horse cannot participate more than once!!!

Answer / animesh sonkar

Divide the horses in 5 groups of 5

Group1 : 5 horses
Group2: 5 Horses
…
Group 5: 5 horses

Race horses of each group so we have 5 races now

1. Take the winner of each groups and create group 6
2. Also from each group keep a mark of second and
third finishers
3. Race group six we have top 3
4.

If top 3 horses were distributed in different groups then
we have them in minimum 6 races…


But bad scenarios:
Case 1: Horse rank 1 and 2 were in same group
Case 2: Horse rank 1 and 3 were in same group
Case 3: Horse Rank 1 2 and 3 were in same group
Case 4: Horse rank 2 and 3 were in same group

So from group six we can safely remove last two horses
whatever the scenario….

Also from group six we can remove the rank1 horse which we
know after six races is rank1

Group six now has 2 horses.
Case 1 ,2 and 3: Take the 2nd and 3rd position horse from
the group where rank 1 horse belongs

Make this as group 7:
Race the horses, the winner is rank 2 horse horse (total 7
races till now).
Remove the horse from group as rank 2. We have 3 horses now

Put these horses In group8

If rank2 horse is from the same group as rank 1 from the
initial groups
Then the horse which came third is rank 3 horse

If rank2 horse is from other group than rank 1 horse, then
pick the horse finished 2nd from the original group where
rank 2 horse belongs.
Add this horse to group 8 and race the horse
The winner of the race is rank 3 horse.

So if it is a worst case scenario we will need 8 races

Answer / 1

11

Answer / emma christian

You use an eletronic tag in each horse and place some sort
of scanner beam over the finishing line so it can catalog
which order the chips come in, and then work out with horse
came second. Or you could use a camera and freze it frame
by frame to work it out.

Answer / alphy

Ans 6

race the horses as 5 times each contains 5 horses.
so 5 races and we will get 5 toppers in each race.

so conduct one more race with these 5 and the 2nd comng is the
one mentioned in the question.

so total 6 races.

Answer / pramodh

Ans: 5
as the horses can participate only in one race so the first
from the 5 races conducted among 5*5 horses are selected as
best five as provided that there is no stop clock

Answer / ram kumar.y

first thing is its impossible to answer this question. it
can be best answered if the last stipulation is neglected
"obviously, a horse cannot participate more that once in a
race".
conduct 5 races for all the 25 horses 5 at a time. and
conduct another(6th) for the winners of the five races
conducted earlier. so the the horse that comes second in the
final race is the second coming horse.

What is the syllabus for numerical aptitude exam to be held by the United bank of India. Plz inform me through email. Thanking You!

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