Answer / .....

initially while inserting image into database take the
database field in oracle as BLOB in sql as image

during insertion convert the image file into bytes and
insert it into the database

during the display of image in datagrid take a image
template and display the converted values
sample code to get the image:
public byte[] spic(string cm,int id)
{
con = new OracleConnection(cm);
OracleCommand cmd = new OracleCommand("select
photo from kir_image where eid= "+id +" ", con);
con.Open();
byte[] img = (byte[])cmd.ExecuteScalar();
con.Close();
return img;
}

use Response.BinaryWrite to display the image

Answer / nagaraj

pls post a mail to below mail id answer if any knows

Answer / krishnasamy2008

Using C#(Asp.net)
-------------
<asp:TemplateColumn HeaderText ="Photo" >
<ItemTemplate>
<asp:image

</ItemTemplate>
<asp:Image ID="udphoto" ImageUrl='<%#Eval("Photo")%>'
runat="server" />
<HeaderStyle ForeColor ="blue" />
</asp:TemplateColumn>

Using Vb.Net(Asp.net)
-------------
<asp:TemplateColumn HeaderText ="Photo" >
<ItemTemplate>
<asp:image

</ItemTemplate>
<asp:Image ID="udphoto"
ImageUrl='<%#DataBinder.Eval(Container.DataItem,"Photo")%>'
runat="server" />
<HeaderStyle ForeColor ="blue" />
</asp:TemplateColumn>

Answer / deepika

Use template column and put image as control in the
itemTemplate

Answer / appu

<asp:GridView ID="GridView1" runat="server"
AutoGenerateColumns="False" DataKeyNames="ID"
DataSourceID="SqlDataSource1">
<Columns>
<asp:BoundField DataField="ID" HeaderText="ID"
InsertVisible="False" ReadOnly="True"
SortExpression="ID" />
<asp:BoundField DataField="ImageName" HeaderText="ImageName"
SortExpression="ImageName" />
<asp:TemplateField HeaderText="Image">
<ItemTemplate>
<asp:Image ID="Image1" runat="server"
ImageUrl='<%# "Handler.ashx?ID=" + Eval("ID")%>'/>
</ItemTemplate>
</asp:TemplateField>
</Columns>
</asp:GridView>
<asp:SqlDataSource ID="SqlDataSource1" runat="server"
ConnectionString="<%$ ConnectionStrings:ConnectionString %>"
SelectCommand="SELECT [ID], [ImageName], [Image]
FROM [Images]"></asp:SqlDataSource>
Handler.ashx


<%@ WebHandler Language="C#" Class="Handler" %>

using System;
using System.Web;
using System.Configuration;
using System.Data.SqlClient;

public class Handler : IHttpHandler {

public void ProcessRequest (HttpContext context)
{
SqlConnection con = new SqlConnection();
con.ConnectionString = ConfigurationManager.ConnectionStrings
["ConnectionString"].ConnectionString;

// Create SQL Command
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "Select ImageName,Image from Images" +
" where ID =@ID";
cmd.CommandType = System.Data.CommandType.Text;
cmd.Connection = con;

SqlParameter ImageID = new SqlParameter
("@ID", System.Data.SqlDbType.Int);
ImageID.Value = context.Request.QueryString["ID"];
cmd.Parameters.Add(ImageID);
con.Open();
SqlDataReader dReader = cmd.ExecuteReader();
dReader.Read();
context.Response.BinaryWrite((byte[])dReader["Image"]);
dReader.Close();
con.Close();
}

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