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i have a jcl in which 4 & 5 step creates a new generation.
4th step output is as input for the 6th step & 5th step
output is used as input in the 7th step. How they are
refered as in the 6th & 7th steps?
If the job abends in 6th step then how the 5th step output
is refered in 7th step?

Answers were Sorted based on User's Feedback



i have a jcl in which 4 & 5 step creates a new generation. 4th step output is as input for the ..

Answer / sivakumar sekharannair

In the question it says that in step 4 and 5 a new
generation is created. so
Step 4 output: XX17.PRASAD.OUT1(+1) This step can be
referred as in Step6.
so step 6 will refer this file as XX17.PRASAD.OUT1(+1)
generation only. because (+1) will become current version
(0) only after the execution of the entire job.
Similarly
Step 5 output: XX17.PRASAD.OUT2(+1)
so step 7 will refer this file as XX17.PRASAD.OUT2(+1).
If the job abends in step 6. the files created in step 4
and 5 will become current version (0).
so now the 7th step will refer the output of step 5 as (0)
i.e.XX17.PRASAD.OUT2(0).

Note:
I assume the files created by step4 and step5 are different.

Is This Answer Correct ?    8 Yes 0 No

i have a jcl in which 4 & 5 step creates a new generation. 4th step output is as input for the ..

Answer / nimsatprasad

Ex:

Step 4 output: XX17.PRASAD.OUT(+4) This step can be
referred as in Step6.

Step 5 output: XX17.PRASAD.OUT(+5) This step can be
referred as in Step7.

If the Job bends in 6the step so already 5th step has been
processed successfully. So we can restart from the step6
then we can refer the 5th step output to 7th step input as
current version.

After abend:

Step 5 output: XX17.PRASAD.OUT(+5) This step can be
referred as XX17.PRASAD.OUT(0) in Step7 after abends the
job.

**** Please let me know if it is wrong.

Is This Answer Correct ?    1 Yes 0 No

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