Answer / kangchuentat

REACTION ENGINEERING - ANSWER 13.2 : (a) Cb = (1000 g / L) / (18 g / mol) = 55.556 mol / L. (b) X = 1 - 1 / exp [ kt (Cb) ] = 1 - 1 / exp (0.00083 x 45 x 55.556) = 0.8744. (c) X = 1 - 1 / exp [ kt (Cb) ], 1 / exp [ kt (Cb) ] = 1 - X, exp [ kt (Cb) ] = 1 / (1 - X), (Cb) kt = ln [ 1 / (1 - X) ], t = 1 / [ k (Cb) ] ln [ 1 / (1 - X) ] = ln [ 1 / (1 - X) ] / [ k (Cb) ]. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

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