Question 66 – The drag coefficient Cd = 0.05 and lift coefficient Cl = 0.4 for a levelled flow aircraft are measured. The velocity of the aircraft is v = 150 ft / s with its weight W = 2677.5 pound-force. (a) Find the value of the lift of the aircraft, L, when it is also its weight. (b) The drag of the aircraft, D = Cd M, L = Cl M. Find the value of D. (c) The power required is P = Dv. If 1 pound-force x (ft / s) = 1.356 W, find the value of P in the unit of Watt or W.
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Answer / kang chuen tat (malaysia - pen
Answer 66 – (a) L = W = 2677.5 pound-force. (b) D / L = Cd / Cl, then D = (Cd / Cl) L = (0.05 / 0.4) (2677.5) = 334.6875 pound-force. (c) P = Dv = 334.6875 (150) (1.356) = 68075.4375 W, where D has a unit of pound-force and v has a unit of ft / s.The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.
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