My source is this
year
01/jun/2014
04/may/2015
09/mar/2017
my desired output is
day month ye
01 jun 2014
04 may 2015
09 mar 2017
how do i acheive this
Answers were Sorted based on User's Feedback
Answer / kumar
use reg_extract
refer this link
https://etltechsolutions.wordpress.com/2016/06/01/using-reg_extract/
its has the logic u need to change a bit as you have char as month.
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Answer / isha
to_char(to_date(Date, 'dd/mon/yyyy'), 'dd mon yyyy')
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what are the types of Data warehousing ?
rank() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid order by case when opt2.dm_market_flg in ('Y', 'U') then 1 else 2 end, lkp.contact_rank) as rank1, case opt2.contact_type when 'Buyer' then row_number() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid, lkp.contact_rank order by has_name_flg desc, ship_to_flg desc , last_order_dt desc) when 'Decision Maker' then row_number() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid, lkp.contact_rank order by has_name_flg desc , last_quote_dt desc , mailability_score desc , source_ranking desc) when 'Influencer' then row_number() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid, lkp.contact_rank order by has_name_flg desc, mailability_score desc, source_ranking desc) when 'Payer' then row_number() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid, lkp.contact_rank order by has_name_flg desc, mailability_score desc, source_ranking desc) --elu 05/28/2013 else row_number() over (partition by opt2.dim_plat_site_id, opt2.dim_site_opt_sid, lkp.contact_rank order by has_name_flg desc, mailability_score desc, source_ranking desc) end rank2 row_number() over (partition by opt3.dim_plat_site_id, opt3.dim_site_opt_sid order by rank1,rank2) as "rank", case when "rank"<= opt3.maximum_value then 'Y' else 'N' end as include_flg
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