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Hi Frnds this que is recently asked at IBM
there are two rows like aa6588fhfhf,gru282vbvv.
Question is howcan we retrive the first number from two
rows.
Can any one help
thanks in advance
- 5 Answers
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Answer / tdguy
I hope substr function can be used but somewhat lengthy.
But UDF would make task easy.
SEL SIX
FROM
(
SEL
CASE
WHEN SUBSTR(COLUMN,1,1) IN
('1','2','3','4','5','6','7','8','9','0')
THEN '1' ELSE '' END AS ONE,
CASE
WHEN SUBSTR(COLUMN,2,1) IN
('1','2','3','4','5','6','7','8','9','0')
THEN '2' ELSE '' END AS TWO,
CASE
WHEN SUBSTR(COLUMN,3,1) IN
('1','2','3','4','5','6','7','8','9','0')
THEN '3' ELSE '' END AS THREE,
CASE
WHEN SUBSTR(COLUMN,4,1) IN
('1','2','3','4','5','6','7','8','9','0')
THEN '4' ELSE '' END AS FOUR,
SUBSTR(TRIM(ONE||TWO||THREE||FOUR),1,1) AS FIVE,
SUBSTR(COLUMN,FIVE,1) AS SIX
FROM TABLE
) A
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / pavan
sel (case
when position('1' in name)>0 then substring(name from position('1' in name) for 1)
when position('2' in name)>0 then substring(name from position('2' in name) for 1)
when position('3' in name)>0 then substring(name from position('3' in name) for 1)
when position('4' in name)>0 then substring(name from position('4' in name) for 1)
when position('5' in name)>0 then substring(name from position('5' in name) for 1)
when position('6' in name)>0 then substring(name from position('6' in name) for 1)
when position('7' in name)>0 then substring(name from position('7' in name) for 1)
when position('8' in name)>0 then substring(name from position('8' in name) for 1)
when position('9' in name)>0 then substring(name from position('9' in name) for 1)
when position('0' in name)>0 then substring(name from position('0' in name) for 1)
else substring(name from 0 for 1)
end),name from ttemp.t2sel (case
when position('1' in name)>0 then substring(name from position('1' in name) for 1)
when position('2' in name)>0 then substring(name from position('2' in name) for 1)
when position('3' in name)>0 then substring(name from position('3' in name) for 1)
when position('4' in name)>0 then substring(name from position('4' in name) for 1)
when position('5' in name)>0 then substring(name from position('5' in name) for 1)
when position('6' in name)>0 then substring(name from position('6' in name) for 1)
when position('7' in name)>0 then substring(name from position('7' in name) for 1)
when position('8' in name)>0 then substring(name from position('8' in name) for 1)
when position('9' in name)>0 then substring(name from position('9' in name) for 1)
when position('0' in name)>0 then substring(name from position('0' in name) for 1)
else substring(name from 0 for 1)
end),name from ttemp.t2;
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / santosh
sel regexp_substr('aa6588fhfhf','[[:digit:]]+')
Ans:6588
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ashutosh gautam
Use DIGITS("aa6588fhfhf") in transform it will return only
digit as 6588.
| Is This Answer Correct ? | 1 Yes | 2 No |
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