Answer / harish

only #2 is d right answer......XOR yields...perfect answers.....

Answer / balasubramanian ganapthi

a=a+b-(a=b);

This is the example by using only one line to swap the two
variables without using the third variable.

Answer / ashesh anand

Thanks Guys....
#2 is absolutely right...

Answer / xeon

To note on the answer about Perl, it uses a third variable
and just doesn't tell you. The C++ equivalent is:

//Our data
class exampleclass {};
exampleclass classa, classb;
int inta, intb;
float floata, floatb;

//Our swap function
template<class T>
void swap(T *a, T *b) {
T temp = *a;
a = b;
*b = temp;
}

//Our use of the swap function
swap<classexample>(classa, classb);
swap<int>(inta, intb);
swap<float>(floata, floatb);

And also note, Perl is an interpreted (Script) language, so
though it is simple and robust, it is less efficient than a
language that is compiled.

Answer / dipak

#51 is perfect solution.

Answer / raja sekhar sharma

a=a+b;
b=a-b;
a=a-b;

Answer / ankit goel

Sorry i dont know..??
only 1st ans is write......
so give me positive marking....
Thank You...

Answer / pallabi

if any one of the variables eithet A or B is negative or
else both r negatibe then how logic will vary in cobol?

Answer / indu b

a=10;
b=20;
a=a+b;
b=a-b;
a=a-b;
a=20,b=10;

Answer / sriram

Hey guys, what about swaping variables contains string
values? All of your solutions will suck... Try this and swap
any datatype without third variable... Happy Sensible Coding..

$v = 'sriram';
$u = 'lakshmi';

$v .= $u;
$u = substr($v,0,(strlen($v) - strlen($u)));
$v = substr($v,(strlen($v) - strlen($u)-1), strlen($v));

echo 'u = ' . $u .'<br>';
echo 'v = ' . $v;

Is the following code legal? void main() { typedef struct a aType; aType someVariable; struct a { int x; aType *b; }; }

1 Answers  

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3 Answers  

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1 Answers  

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3 Answers  

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6 Answers  

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2 Answers  

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11 Answers   Deshaw, Infosys,