How to swap two variables, without using third variable ?
Answers were Sorted based on User's Feedback
Answer / harish
only #2 is d right answer......XOR yields...perfect answers.....
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / balasubramanian ganapthi
a=a+b-(a=b);
This is the example by using only one line to swap the two
variables without using the third variable.
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / xeon
To note on the answer about Perl, it uses a third variable
and just doesn't tell you. The C++ equivalent is:
//Our data
class exampleclass {};
exampleclass classa, classb;
int inta, intb;
float floata, floatb;
//Our swap function
template<class T>
void swap(T *a, T *b) {
T temp = *a;
a = b;
*b = temp;
}
//Our use of the swap function
swap<classexample>(classa, classb);
swap<int>(inta, intb);
swap<float>(floata, floatb);
And also note, Perl is an interpreted (Script) language, so
though it is simple and robust, it is less efficient than a
language that is compiled.
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / ankit goel
Sorry i dont know..??
only 1st ans is write......
so give me positive marking....
Thank You...
| Is This Answer Correct ? | 8 Yes | 7 No |
Answer / pallabi
if any one of the variables eithet A or B is negative or
else both r negatibe then how logic will vary in cobol?
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / sriram
Hey guys, what about swaping variables contains string
values? All of your solutions will suck... Try this and swap
any datatype without third variable... Happy Sensible Coding..
$v = 'sriram';
$u = 'lakshmi';
$v .= $u;
$u = substr($v,0,(strlen($v) - strlen($u)));
$v = substr($v,(strlen($v) - strlen($u)-1), strlen($v));
echo 'u = ' . $u .'<br>';
echo 'v = ' . $v;
| Is This Answer Correct ? | 1 Yes | 0 No |
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