Answer / susie

Answer :

Compiler Error

Explanation:

in the end of nested structure yy a member have to be
declared.

Answer / dayana benny

The structure yy is nested within structure xx. Hence, the elements are of yy are to be accessed through the instance of structure xx, which needs an instance of yy to be known. If the instance is created after defining the structure the compiler will not know about the instance relative to xx. Hence for nested structure yy you have to declare member.

why the range of an unsigned integer is double almost than the signed integer.

1 Answers  

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Is the following code legal? void main() { typedef struct a aType; aType someVariable; struct a { int x; aType *b; }; }

1 Answers  

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source code for delete data in array for c

1 Answers   TCS,

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abcdedcba abc cba ab ba a a

2 Answers  

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

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main() { int i=-1; -i; printf("i = %d, -i = %d \n",i,-i); }

1 Answers  

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void main() { int const * p=5; printf("%d",++(*p)); }

3 Answers   Infosys, Made Easy, State Bank Of India SBI,

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void main() { char ch; for(ch=0;ch<=127;ch++) printf(“%c %d \n“, ch, ch); }

1 Answers  

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void main() { void *v; int integer=2; int *i=&integer; v=i; printf("%d",(int*)*v); }

1 Answers   Honeywell,

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#include<stdio.h> main() { struct xx { int x=3; char name[]="hello"; }; struct xx *s; printf("%d",s->x); printf("%s",s->name); }

3 Answers   Hexaware,

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void main() { unsigned giveit=-1; int gotit; printf("%u ",++giveit); printf("%u \n",gotit=--giveit); }

1 Answers  

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main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5

2 Answers   HCL,

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