Answer / thilaga

Clearly ans is d.
1<<0 times is 0001.so in decimal 1.
1<<1 times is 0010.so in decimal 2.
1<<2 times is 0100.so in decimal 4.
1<<3 times is 1000.so in decimal 8.
1<<4 times is 0001 0000.so in decimal 16.
thus it becomes 1,2,4,8,16.

Answer / guest

d) L does't make any diff.

Answer / karthi

b.o,1,2,3,4

Answer / aditi

none of them is correct...

coz l does'nt make any diff...

and << means a left shift

o in binary is 0 only...
and wen it is lft shfted it remains same...
1 in binary is 01 >> makes it 010 i.e 2
nd so on...

main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

2 Answers  

---

can you use proc sql to manpulate a data set or would u prefer to use proc report ? if so why ? make up an example and explain in detail

0 Answers   TCS,

---

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

2 Answers   CNSI,

---

#include<stdio.h> int main() { int a=3,post,pre; post= a++ * a++ * a++; a=3; pre= ++a * ++a * ++a; printf("post=%d pre=%d",post,pre); return 0; }

3 Answers  

---

Cau u say the output....?

1 Answers  

---

abcdedcba abc cba ab ba a a

2 Answers  

---

void main() { int x,y=2,z; z=(z*=2)+(x=y=z); printf("%d",z); }

4 Answers  

---

Is the following code legal? void main() { typedef struct a aType; aType someVariable; struct a { int x; aType *b; }; }

1 Answers  

---

#define max 5 #define int arr1[max] main() { typedef char arr2[max]; arr1 list={0,1,2,3,4}; arr2 name="name"; printf("%d %s",list[0],name); }

1 Answers  

---

There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

1 Answers  

---

main(){ unsigned int i; for(i=1;i>-2;i--) printf("c aptitude"); }

2 Answers  

---

#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

1 Answers  

---