Answer / guest

a)

Answer / govind verma

OK I am done. reason bollean expression in if evaluate in such manner first (1||0) will execute and first expresiion of this boolean expression is one so control will not goes to chek any thing i.e whole expression evaluate as (1||0)as 1(true) now expression becom like dis if(1&&(0||1))
now (0||1) expressiion will evaluate in this expression value of left hand side of || operator is 0(false) so control goes to check further and right hand side it recieve 1 then the value of wholl expression becom 1 thn nw orignal expression looks like if(1&&1)
nw (1&&1) is evalute in this case control check both the value of the operator(&&) is one then this return 1 otherwise return 0 then orignal expression like this if(1)
1 is nonzero value this mean condition is true then code of if block will be execute which is OK I am done.

Answer / naveen kumar

ok i am gone...because in this case the condition if((1||0)
&&(0||1)
always remain true. hence the answer is ok i am done...i.e.
(a

Answer / priti soni

d

Answer / karthi

c.compile error

#include <stdio.h> #define a 10 main() { #define a 50 printf("%d",a); }

2 Answers  

---

why array index always strats wuth zero?

2 Answers  

---

main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

1 Answers   CSC,

---

Is it possible to print a name without using commas, double quotes,semi-colons?

7 Answers  

---

How to palindrom string in c language?

6 Answers   Google,

---

---

main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513

3 Answers   HCL, Logical Computers,

---

#define prod(a,b) a*b main() { int x=3,y=4; printf("%d",prod(x+2,y-1)); }

1 Answers  

---

1 o 1 1 0 1 0 1 0 1 1 0 1 0 1 how to design this function format in c-language ?

2 Answers  

---

main() { printf("%x",-1<<4); }

3 Answers   HCL, Sokrati, Zoho,

---

main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }

1 Answers  

---

Write a routine that prints out a 2-D array in spiral order

3 Answers   Microsoft,

---

main( ) { static int a[ ] = {0,1,2,3,4}; int *p[ ] = {a,a+1,a+2,a+3,a+4}; int **ptr = p; ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *++ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); ++*ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); }

2 Answers   Persistent,

---