Answer / p.muthukumar

b=a-b;
a=a-b;
b=a+b;

Answer / 3uggy3oy

Answer #16 is totally wrong it fails
when x>y and many other situation.

Answer / alex

When swapping integers or characters, use:
a^=b;
b^=a;
a^=b;
When swapping floats or doubles use:
a+=b;
b=a-b;
a=a-b;
When swapping strings use:
a=(char*)((int)a^(int)b);
b=(char*)((int)a^(int)b);
a=(char*)((int)a^(int)b);
This works by modifying the address values of the pointer.

Answer / shubham

NOne of the answer is correct except the 2ND one.....Please
don't give wrong answers.

Answer / hanmanth reddy

a=a+b-(b=a);

Answer / bhaskar.mantrala

void main()
{
int a,b;
clrscr();
printf("\n Enter the values of a and b ");
scanf(" %d %d ", &a,&b);
a=a*b;
b=a/b;
a=a/b;
printf("\n \n After swapping ----> a = %d \t b = %d",a,b);
getch();
}

Answer / trinath somarouthu

using X-OR
#define SWAP(x,y) x^=y^=x^=y

x = x ^ y --> x^=y -- (1)
y = y ^ x --> y^=x -- (2)
x = x ^ y --> x^=y -- (3)

(3) in (2) --> y^=x^=y -- (4)
(4) in (1) --> x^=y^=x^=y -- :-)

all togeather, he single line code

#define SWAP(x,y) x^=y^=x^=y

Answer / sunil kharat

a^=b^=a^=b;

try it...
it works. one line solution

Answer / sujata

i think first is right.

Answer / perl guru

($a,$b)=($b,$a)
....this is how we do in PERL....Ha Ha Ha pretty cool !!!!

And BELIEVE me it works not only for NUMBERS but also for
STRINGS, ARRAYS or any Data Structure or any garbage
value....this is mine Challenge.....

None of the any programming language can come close to PERL
in this much of SIMPLICITY and ROBUSTNESS....just one line
does the Magic....

Again I would say the Question itself is very silly one "How
to swap two variables, without using third variable
?"....and I see alot of stupid Answers posted here....

Everyone posting the answer is assuming that Question is
about swapping INTEGER NUMBERS....I would like to ask what
if I provide FLOATING POINT NUMBERS, NEGATIVE NUMBERS, REAL
NUMBERS, and surely it does not work for STRINGS....

That is why I say "Perl is immensely powerful. If you think
something can't be done, the problem is likely to be it is
beyond your ability, not that of Perl."

Welcome to the world of PERL....its more precious than PEARL....

main() { int i = 0xff ; printf("\n%d", i<<2); } a. 4 b. 512 c. 1020 d. 1024

2 Answers   HCL,

main( ) { int a[ ] = {10,20,30,40,50},j,*p; for(j=0; j<5; j++) { printf(“%d” ,*a); a++; } p = a; for(j=0; j<5; j++) { printf(“%d ” ,*p); p++; } }

1 Answers  

main() { unsigned char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

1 Answers  

void main() { if(~0 == (unsigned int)-1) printf(“You can answer this if you know how values are represented in memory”); }

1 Answers  

x=2 y=3 z=2 x++ + y++; printf("%d%d" x,y);

2 Answers  

main() { while (strcmp(“some”,”some\0”)) printf(“Strings are not equal\n”); }

1 Answers  

How do you verify if the two sentences/phrases input is an anagram using predefined functions in string.h and by using arrays?

0 Answers  

why is printf("%d %d %d",i++,--i,i--);

4 Answers   Apple, Cynity, TCS,

how to return a multiple value from a function?

5 Answers   Wipro,

What is the difference between proc means and proc tabulate ? explain with a simple example when you have to use means or tabulate?

1 Answers  

pls anyone can help me to write a code to print the values in words for any value.Example:1034 to print as "one thousand and thirty four only"

2 Answers  

main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,