Answer / arindam

b=(a+b)-(a=b);

Answer / shruti dengre

answer no. 6th is is correct

Answer / suseela

for ex x=10,y=20
x=x+y=30(i.e 10+20)
y=x-y=10(i.e 30-20)
x=x-y=20(i.e 30-10)

Answer / shubham

#include<stdio.h>
#imclude<conio.h>
main()
{
int a,b;
printf("enter two number");
scanf("%d%d",&a,&b);
b=a-b;
a=a-b;
b=a+b;
printf("after swaping &d",swap);
getch();
}

Answer / lokesh

a=a-b;
b=a-b;
a=a+b;

Answer / praveen kumar telluri

b=a*b/(a=b);

Answer / naveen

Using a single line statement:

a=(a+b)-(b=a)

Answer / hamsa

a=a+b;
b=a-b;
a=a-b;

ex a=2, b=4

a=2+4
b=6-4
a=6-2


ANS a=4
b=4

Answer / debjyoti talukder

a=a+b;
if(a>b)//only the smaller can b subtracted from greater...
b=a-b://...reverse is not possible
else
b=b-a;
a=a-b;

Answer / swapnil r

Swapping two variables

1. #define SWAP(x,y) x^=y^=x^=y

2. a=a+b;
b=a-b;
a=a-b;

3. use xor to swap

a = a^b
b= a^b
a= a^b
4. a=a*b;
b=a/b;
a=a/b;

could you please send the program code for multiplying sparse matrix in c????

0 Answers  

There is a lucky draw held every day. if there is a winning number eg 1876,then all possible numbers like 1867,1687,1768 etc are the numbers that match irrespective of the position of the digit. Thus all these numbers qualify fr the lucky draw prize Assume there is no zero digit in any numbers. write a program to show all the possible winning numbers if a "winning number"is passed as an arguments to the function.

1 Answers   Nagarro,

main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); }

6 Answers  

main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,

int i,j; for(i=0;i<=10;i++) { j+=5; assert(i<5); }

3 Answers   Cisco, HCL,

Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error

3 Answers   HCL,

plz send me all data structure related programs

2 Answers  

pls anyone can help me to write a code to print the values in words for any value.Example:1034 to print as "one thousand and thirty four only"

2 Answers  

main( ) { static int a[ ] = {0,1,2,3,4}; int *p[ ] = {a,a+1,a+2,a+3,a+4}; int **ptr = p; ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *++ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); ++*ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); }

2 Answers   Persistent,

How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }

1 Answers