There is a variable with value 19446. Requirement is to
convert it to 194.46. I tried it by doing divide by 100 and
my receiving field data type is 9(03)v99. But the output is
194. I am not getting the decimal value. Could anyone pls
let me know how to get this done?
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Answer / kiro
When COBOL does a divide it uses the format of the item
which in this case is integer only that is why the
fractional part is missing. You need to move the value
19446 to a 9(5)v99 item first and then do the divide using
the 9(5)v99 item.
| Is This Answer Correct ? | 7 Yes | 0 No |
To make this we require to use redefines.
01 ws-value-change
05 WS-ALPHANUMERIC PIC X(5).
05 WS-NUMERIC REDEFINES WS-ALPHANUMERIC PIC 9(3)
V99.
011 WS-EDITED-NUMERIC PIC 9(3).99.
PROCEDURE DIVISION
MOVE '19446' TO WS-ALPHANUMERIC
MOVE WS-NUMERIC TO WS-EDITED-NUMERIC
DISPLAY WS-EDITED-NUMERIC
STOP RUN
You will get the value as 194.46
| Is This Answer Correct ? | 7 Yes | 0 No |
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consider the following progrm statements MOVE 0 TO SW.NO.OF.REC PERFORM PRI-OUT UNTIL SW=1 DISPALY NO.OF.REC STOP RUN PRE-OUT READ IN-FILE AT END MOVE 1 TO SW WRITE OUO-REC FROM IN-REC ADD 1 TO NO.OF REC if the IN-FILE contains 1000 records what value will be displayedafter the PERFORM is over?assume that N0.OF.REC has PIC 9(4) a.1000 b.1001 c.1 d.none of the above since there is a syntex error
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