01 a pic x(6) value is abcdef
01 b pic x(3)
move a to b wht will be the value in b ?
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How many bytes will be allocated for the following record description entries? 01 REC-A. 05 A PIC S9(4). 05 B PIC XXXBXXX. 05 C PIC ____9.99. 05 D PIC S9(5) COMP-3. 05 E PIC 9(3) COMP.
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01 ws-p pic 9(2). 01 ws-q pic 9(2) value 01. 01 ws-r pic 9(2) value 99. p.d. compute p = q + r what will be result of p ans(00) but my question is that how i got 10 on the place of 00. (truncation will ocuure on right side not left). please tell me ?
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