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77 I pic 99 value 5
Perorm para-A I times.
Para -A.
move 10 to I.
How many times the para-A will be executed.?
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Answer / rana
Only 5 Times as it won't take the 10 which is intialized in
Para-A.
| Is This Answer Correct ? | 16 Yes | 4 No |
Answer / sivaram
It goes into loop since the variable takes the 10 in it
every time when it performs.Generally the variable should be
decremented by 1 for correct results.
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / kiran
5 times
why bcoze once para-A I times executed,initially the value
of i=5;
5 time para -A executed
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / gowtham
Hi, I have executed above code and it performed 6 times. SO the answer is 6 times.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / chinna
Please confirm which ans is correct ?
why it wont take I = 10?
can any one give explanation ?
Thanks ,
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / suputhru
Para -A.
move 10 to I.
display I.
it will move 10 to I upto 5 times.
10 20 30 40 50.
it will execute 5 times only.
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / prachi
when it will execute perform statement for the first time,
the value in i is 5..Then it is moving 10 to i ..So when it
will execute the perform 2nd time...that time the value of
i is 10..so Para-A will be performed 11 times...
Please let me know my ans is correct or not...
| Is This Answer Correct ? | 0 Yes | 3 No |
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