Answer / shahidha

300

Answer / karan_intouch

N(A u B u C) = N(A)+N(B)+N(C)-N(A n B)-N(B n C)-N(C n A)+N(A
n B n C)

4000 = 1500 + 2000 + 2500 – 800 – 1000 – 800 + N(A n B n C)

Hence N(A n B n C) = 300

Answer / chaitu

Well... The Answer is quite simple...
From the basic formula
(Intersection of A,B= A+B- Union of A,B)

Apply above formula for 3 variables.

Intersection of A,B&C= 1500+2000+2500-800-500-1000-4000
= -300

Therefore, 300 is the Answer....

Answer / puru vatsa

Total no. of People = 4000
500 people watch A and B channel and 800 people watch A and C
and 1500 watch A channel.
Hence people who watch only A = 1500-(500+800) = 200
Similarly people who watch only B = 2000-(500+1000) = 500
and people who watch only C = 2500-(800+1000) = 700
Hence total no. of people watching these channels =
200+500+700+500+800+1000 = 3700
Hence people watching A,B,C = 4000 - 3700 = 300 (Ans)

Tip :- Draw Venn-Diagram and then solve.

Answer / mannu

That qustion is wrong

Answer / kiran

100
as
people watching only a channel=200
only b channel=700
only c channel=700
total=1600
now a+b=500
b+c=1000
c+a=800
total=2300
new total=3900
so 4000-3900=100

Answer / guest

100

Answer / yaswanthraj

Well.....500 watch A and B ....(2000-15000)...obvious
and 800 watch A and C...
Actually....A:1500;c:2500
So both A and C==> intersection(2500-1500=1000)
Given 800

so 1000-800=200

200 watch A,B and C....max channels

and hence it is the answer :-)

Answer / raja

4000

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