Answer / britto

a's i day work =1/10
b's i day work =1/15

a+b = 1/10 + 1/15 = 1/6 is for 1 day....for total days jus
reciprocal of it is 6...

Answer / hradayeshkumar sharma

If x is the total amount of work to be done, then
a does x/10 of work in one day while,
b does x/15 of work in one day
If y is the number of days that a and b have to work
together to finsh x amount of work then the equation becomes

(x/10)*y + (x/15)*y = x

which results into y = 6.

Answer / sri

THE ANS IS 6.
the problems of this kind are done using the formula
like if A can do a piece of work in n days then A's 1 day
work is 1/n. similar case with B let it be 1/m.
then to find out the work done by both A and B the no.of
days is to add (1/n + 1/m) by finding L.C.M, simplifying it
and reciprocal gives the no. of days.
here A's work is 1/10
B's work is 1/15
1/10 + 1/15 = 1/6 reciprocate this then the no .of days is 6.

Answer / gaurav goel

a finishes 1/10 work in a day when he does work alone...
b finishes 1/15 work in a day..
when they both work together means a+b...let they do 1/x
work per day when they work together....where x is the no.
of days...
so a+b=... or
1/10 + 1/15 = 1/x ,
(2+3)/30 = 1/x,
1/6 = 1/x,
x=6.......

Answer / rajitha chanda,chennai

(15*10)/(15+10) = 6 (short Cut)

Answer / naman bhardwaj

A WORK 1/10 IN A DAY WHILE B WORK 1/15 IN A DAY
1/10+1/15=1/6 IN ONE DAY THEY BOTH DO 1/6 WORK SO THEY WILL
DO THE THE TOTAL WORK IN 6 DAYS

Answer / banerjee

any time between 6 to 10 days

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