Answer / hari

H2SO4 is acid , when water is added to the acid it will
produce high energy , it is in the form of heat.So from this
we could not add water directly, we have to add it slowly
then we will neutralize the heat.

Answer / dinesh patil

Sulphuric acid has hydroscopic (Affinity towards water)
property. When we add water to acid due to hydroscopic
property it may suddenly comes out & may cause burning.

While mixing water & sulphuric acid we should always add
acid in water (with glass rod) & not to add water in acid.

Heat is genrated called as heat of neuterization which has
no relation with the addition

Answer / gopesh

Actually when water is added to sulphuric acid, a huge
amount of heat generates liable to crack the beaker
this is why when we need to dilute H2SO4 we take water in
a beaker and add acid slowly so that heat generation is
slow .

Answer / harsh

Since, acid is more viscous than water if we add water to
acid mixing will not be proper & thereby heat dissipation
becomes difficult. The added water takes away the
dissipated heat rapidly forming steam & creating a Flashing
or Explosion. Therefore water shouldn't be added to acid
and acid should be added to water for the dilution purpose.

Answer / sania

because on dilution of acid more amount of heat generate
which is harmful for human so water is not directly added to
acid

Answer / murthy

if water is added directly into large amount of H2so4, due
to heat of misibility water is vaporized, water required to
dilute greatly increases approximately 15-20 times .that is
why H2so4 is added to water and water is not added to h2so4.

Answer / sanjay kumar it-bhu

H2SO4 is highly acidic , when water is added to the acid it
will produce high quantiy of energy , it becomes violent
condition means break the beaker.So its dangerous for humen
so there should not be add water directly, we have to add
it slowly in dropwise manner then we will neutralize the
heat.

Answer / priyank sompura

because it is very concentrated so that for concentration
water is not directly used

Question 44 - In a non-dilute absorber, graphical method is used to represent the process. In an X - Y coordinate system, X-axis represents mole of carbon dioxide / mole of water and Y axis represents mole of carbon dioxide / mole of nitrogen. The inlet gas stream consists of 8 mol % of carbon dioxide in nitrogen. (a) Find the S / G minimum as a slope that goes through the point (0, 0.0304) and (0.0000488, 0.086957). (b) Find the actual slope of operating line when it is 1.5 times the S / G minimum! (c) Find the value of x for inlet gas stream when y = 1640 x, y is mole fraction of carbon dioxide in nitrogen.

1 Answers  

hai please please if any one have useful test related and interview based question plz send me at saify_0@hotmail.com i will be thankfull

0 Answers  

Explain how can you determine the proper pipe thickness for a slurry line?

0 Answers  

Is there any way to repair a valve that is passing leaking internally without taking our process offline?

0 Answers  

Explain how can you quickly estimate the horsepower of a pump?

0 Answers  

What is an isochoric process?

0 Answers  

Are there any special considerations to be taken into account for combustion ammonia?

0 Answers  

QUANTUM CHEMISTRY AND CHEMICAL ENGINEERING - EXAMPLE 31.8 : (a) Acceptable wavefunction in quantum mechanics in the range of : negative infinity < x < positive infinity, vanishes at least at one boundary. Which of the following is the wavefunction or are the wavefunctions of acceptable theory : P = x, P = | x |, P = sin x, P = exp (-x), P = exp (-| x |)? State the reason. (b) Let linear momentum operator P = -ih d / dz. The wavefunction is S = exp (-ikz) where i x i = -1, k and h are constants. Find the linear momentum of such wavefunction by using the term P x S.

1 Answers  

POLYMER ENGINEERING - QUESTION 24.2 : Let C% be the fractional crystallinity, Rs = density of sample, Ra = density of amorphous form and Rc = density of crystalline form. In a polymer, these unknowns could be related by the equation C% = (Rc / Rs) (Rs - Ra) / (Rc - Ra). (a) Find the equation of Rc as a function of C%, Rs and Ra. (b) Two samples of a polymer, C and D exist. For sample C, C% = 0.513 when Rs = 2.215 unit. For sample D, C% = 0.742 when Rs = 2.144 unit. Both samples C and D have the same values of Ra and Rc. Find the values of Ra and Rc in 6 decimal places.

1 Answers  

How much will be the increment for postal assistant yearly?

0 Answers  

what is the height between the reflux pump and condenser ?

4 Answers  

what is first order of reaction?

0 Answers   Deepak Fertilisers,