Answer / arvind

see there is formula, u must be knowing that
V=4.44FBN, BECAUSE OF THIS 4.44 ONLY U GOT the voltage in
term sof 11, 22 etc this 4.44 u will get from form factor
which has a value of 1.11.

Answer / nilesh dalvadi

Thers is syatem voltage line is of 400 KV and 750 Kvb which
is ot in multiplication of 11 so thers is something more
behinmd 11

Answer / arun

VOLTAGE LINE ONLY DEPEND UPON FORM FACTOR, THEN FORM FACTOR RATIO IS =RMS VALUE /AVG VALUE= 1.11. THEN ONLY HIGH VOTAGE LINE IN MULTIPLICTION OF 11 SERIES.

Answer / prasad

because form factor is the ratio of rms value to the avg
value.normally for AC current we will consider RMS VALUES
ONLY,because of this we will get 11kv,22kv,33kv...etc

for same rating of a transformer and induction motor which one will have higher magnetising current flowing?

2 Answers  

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What is Black-out and Brown-out situation in the context of voltage stability in power system?

1 Answers  

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Define transfer function?

0 Answers  

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can any one explain about when EB supply failed then how the load will transfer onto DG's step by step.

1 Answers  

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sir,in our plant we r using SATEC PM172E power reading meeters in HT panel side it is monitoring the MB data smart viewer(sever).but last one week we did not get readings inthe server only available in meeter.tell me how communicate meter and server. and also what steps we take for checking.

0 Answers  

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diffrence between alternating and pulsating field?

1 Answers  

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What is the principle of residual protection?

0 Answers  

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STATE USE OF ARC RUNNERS & SPLITTERS ?

0 Answers  

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what is the phase voltage and line voltage in 2 phase power supply?

1 Answers   EID Parry, IBM,

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why dc supply given to ac alternator rotor

3 Answers  

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I want to know the principle of rotating flux transformer.

1 Answers  

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We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?

0 Answers   Siemens,

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