There are 200 questions on a 3 hr examination.Among these
questions are 50 mathematics problems.It is suggested that
twice as much time be spent on each maths problem as for
each other question.How many minutes should be spent on
mathematics problems, plz give detail, how to solve?
Answers were Sorted based on User's Feedback
Answer / harsh
3 hrs=180 mins
suppose time alloted for each que=1 unit
the time alloted to a que other than mathematics=(200-50)
=150 units
since the time spent on a maths question is twice the other
problems, time spent on a maths prob= 50*2=100 units
therefore, 2/5 or [100/(150+100)] of the total time will be
spent on a maths prob
ie 180*(2/5)
=72 mins
Is This Answer Correct ? | 82 Yes | 12 No |
Answer / kishore
50 maths ques
150 remaining ques
the time spent on each math ques is twice the remaining
150x+50(2x) = 180 (min)
x= 18/25
total time on maths ques is 50(2x)
50 * 2 * 18/25 = 72min
Is This Answer Correct ? | 55 Yes | 0 No |
Answer / ashraf
we assume that X is the time taken for each general question
then the time taken for math problem is 2X
then 150X+50(2X)=3hours
then x=(3*60)/250 min
x=18/25 min
then the time taken for math problem is 2X=2*18/25=36/25
Is This Answer Correct ? | 59 Yes | 27 No |
Answer / r.subha
total 200 questions, time duration 3 hours so,1 hour =60 min
so,3 hours=180 mins.
out of 200 questions 50 questions is maths question 150
question is other question.
if you spent x time for 150 question, you spent 2x time for
50 question
so, 50(2x)+150(x)=180
solve ,we got the x value ; x=18/25
150 question 150 x ,we have calculate 150 questions time
so 150(18/25)=108
then total time is 180, we had spent 108 minute for 150
question,so
180-108=72. remaining minute for 50 question is 72
Is This Answer Correct ? | 3 Yes | 0 No |
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