why motor starting current is High ?
Answers were Sorted based on User's Feedback
Answer / y.v.vsurya teja
as in the initial conditions the motor is at rest,the speed
of the motor is zero.
using KVL equation,
V=Eb+IaRa,Eb=back EMF
Ia=armature current
Ra=armature resistance
(very small),V=input supply(around 220V dc)
Initially speed=0
implies Eb=0
Ia=(V/Ra) which is very high value,since V is high
and Ra is very small.
Hence starting resistance or 3 point starter
are used.
Is This Answer Correct ? | 35 Yes | 1 No |
Answer / gajanan
at starting rotor is stationary, due to its inertia it will
require more torque to rotated and torque is proportional
to armature current
so requires more starting current
Is This Answer Correct ? | 46 Yes | 17 No |
Answer / electrical
V=Eb+IaRa,Eb=back emf
At starting there is no back Emf
And V (Normal Supply Voltage)=220V(single Phase)
Ia = Armature Current
Ra = Armature resistance(Usually less (.2 to .5 ohms)
From the Above equation,
Ia = (V-Eb)/Ra
Since Eb is Zero, the above eqn will become
Ia = V/Ra (220/0.5 = 440A)
So at starting the current thru the armature is very high
to minimise this we are using the starters.
Is This Answer Correct ? | 24 Yes | 1 No |
Dear Mr. Gajanan, as you are dealing with more machineries,
i want to stress some points:
During starting of motor:
the armature(rotor) is stationary, and it does not having
any magnetic property to resist the applied rotational
frequency at that time.
so it will act as a conductor fixed at rotating magnetic
field and produce some eddy current loss, and with in short
period of time, it will develope some anti rotional effect
to resist the rotational field, ie: rotating with same
direction to reduce the eddy curent.Thats why after
starting current reduces.
inertia of the rotor also having some major role on the
starting current. The gap between rotor and stator having
role on the starting current and initial power factor.
Is This Answer Correct ? | 22 Yes | 11 No |
Answer / ta
What the persons above said is true mathematically.
If you look at it as in theory, we know a DC Machine can act
as a Motor as well as a Generator. So as the Current is
supplied to the conductors present in a magnetic field, a
Force starts to act on the current carrying conductor. This
current forces the Rotor to rotate. At this time the only
Voltage is the supplied Voltage. As soon as the motion
starts there has to be an Emf induced which directly depends
on the speed of rotor. This induced voltage is called
Counter EMF or the Back EMF, which is absent at the instance
the motor is supplied a current. This EMF in effect acts
opposite to the Supplied Voltage. So whatever Drop of
volatge is in The resistance of Rotor wires is due to the
Total Supplied Voltage and Resistance is pretty low so the
current at the start is very high
Is This Answer Correct ? | 12 Yes | 1 No |
Answer / vijendra joglekar
There are two reasons
1.At starting the motor will behaves as low resistance circuit.
As we know the fundamental i mean when the
resistance is low the current will be high.
2. At starting the back emf will be zero
As we know the voltage equation of motor
V=Eb+Ia Ra
Where Eb is the back emf which is zero at starting
V is they supply voltage
Ra is they armature resistance which is very small
hence we can prove that by using the equation.
Is This Answer Correct ? | 6 Yes | 1 No |
Answer / raul
ARMATURE CURRENT (Ia)= V-E)/Ra, during starting, back emf
E is zero, n supply voltage is practically constant, n
armature resistance is small, so armature current is
initially very high...........
Is This Answer Correct ? | 5 Yes | 0 No |
Answer / ajaysinh
THERE IS NO BACK TO OPPOSE THE INRUSH CURRENT ON SWITCHING.
Is This Answer Correct ? | 2 Yes | 1 No |
Answer / guest
When voltage is first applied to the motor field winding, only the conductor resistance opposes the flow of current to the motor winding. For example a motor winding rated at 240V with a winding resistance of 0.6 ohms. Using Ohms law we find I (current)= E/R or 240V/0.6 ohms = 400Amps.
DURING MOTOR STARTING = LOW RESISTANCE, HIGH CURRENT
Because the conductor resistance is so low, the motor has a very large inrush current.
Once the rotor begins turning, the rotor bars (winding) are increasingly cut by the stationary magnetic field, resulting in increasing counter electromotive force (CEMF).
CEMF opposes the applied voltage, resulting in an increased opposition to current flow within the conductor, which is also called inductive reactance.
The increase in inductive reactance, because of self induction, causes the impedance of the conductor winding to increase and this results to reduced current flow.
Same motor, R=0.6 ohm, XL=6 ohms, V=240 volts
Z = √(R^2+〖XL〗^2 ) = √(〖0.6〗^2+6^2 ) = 6 ohms
I = E/Z = 240V/6Ω = 40Amps
DURING MOTOR RUNNING = LOW RESISTANCE, HIGH INDUCTANCE, LOW CURRENT
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / tawfiq
when we turn on a motor,it induces a relatively high
current to get over the inertia of the motor. this induced
current is estimated to be 7*rated current if the motor was
in direct to line connection
Is This Answer Correct ? | 3 Yes | 4 No |
definition of transponder?
what is thyristor, how is it works
In a 3 phase 4-wire system. For a 3.5 core cable if all loads are single phase and balanced, what will be neutral current? will it be sum of all phase currents? Or it will be zero? And if loads are unbalanced what will be neutral current?
why connecting surge unit in contactor coil
what is the pre charge circuit,what will be work which function it will be use plz tell me
what will happen if the field and armature both are made to rotate in a synchronous machine ?
What is power factof?
Y phase plates are used in transmission line??? what is there need???
Please, if 1kw is equal to 1.25kva; how then do I know how many kva in 7.5kw?
why in US MAINTAIN 60hz,110volts when compared with 50hz,220v in india
What is electrical grounding?
how to distinguish between ac motor and dc motor without seeing name plate of it.only seeing its getup look