Answer / abid ali khattak

For the practically experiment of power factor we need to
connect the two type of same Wattage AC load with the
circuit. 1- inductive load. 2- Resistive load. and then we
need to be measured the current of both laod. We will find
that the inductive load getting more current then resistive
load.( lagging & Leading)
Beacause of inductance which induced in the inductive load.
which always oppose the provided EMF.

Answer / bhaskar

we need one wattmeter, voltmeter and amperemeter each.
observe the readings.
p.f. = Wattmeter reading/(volts*curr),ie. W/V*I

Answer / g.v.suresh kumar

IN PRACTICAL POWER FACTOR IS DEPEND UPON LOAD
IF LOAD INCREASES MEANS RESULTS REDUCE IN P.F

our company have 750 kva oil transformer.still we have facing a problem that is when voltage is 11.5 kv coming from HT side then LT-side voltage is 420v or above at tape 1.please give me best solution to decrease the voltage

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why we measure ouput of transformers in kva.

1 Answers  

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what is the difference between real and reactive power? and what is the importance of these

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purpose of check value

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what happens if dc supply is given and the remedies for it.

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