Answer / kangchuentat

Answer 86 - (a) Phenotypes of parents = gray wingless, black winged. Phenotypes of recombinant children = gray winged, black wingless. Number of recombinant children = gray winged + black wingless = 115 + 95 = 210. Recombination frequency between the two genes = Number of recombinant children / Total number of childen = 210 / (210 + 890 + 900) = 0.105 or 10.5 % = distance = 10.5 map units. (b) Base pairs number of adenine = 180 x 0.2 = 36 = base pairs number thymine. Base pairs number of guanine = base pairs number cytosine = (Total number of base pairs - 2 x Base pairs number of adenine) / 2 = (180 - 2 x 36) / 2 = 54. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

what is the relation between velocity & pressure. tel me if pressure in water line is increased what wil b effect on velocity ?

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.7 : An engineering investor purchases a $1000 bond that matures in 25 years. The coupon rate is 8 %. The purchase price is at 95 or 95 % of the par bond value. (a) What is the purchase price of the bond? (b) How much discount is enjoyed by the investor on average each year? (c) Find the income generated from coupon rate each year. (d) Find the overall interet rate or Yield to Maturity (YTM) by using the formula : YTM = [ Answer in (c) + Answer in (b) ] x 200 / [ par bond value + Answer in (a) ].

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Hi, Please give me chemical engineering paper for IOCL exam for entire written exam, GD and personel interview model questions to my email id. (chemistnathan@rediffmail.com) Rgds, Ragu

0 Answers   HAL, IOCL,

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