I know during Surge Impedance Loading maximum power is
transferred through a transmission line and also Sending end
voltage becomes equal to Receiving end voltage i.e Vs=Vr so
my question is if both end voltages are equal then how
current travels in such line hence how power is transmitted
because flow of current needs Potential difference??
Answers were Sorted based on User's Feedback
Answer / gopal
actually here we are dealing with phasors in AC system .and
Vs and Vr are equal in magnitude but not in phase angle.
power flows from Vs/_ᵟ to Vr/_0 according to the equation of
real power flow
P= Vs Vr Sin(ᵟ) Vs/_ᵟ - Vr/_0
------ = ---------------
Xs I
actually in phasors although their magnitude is equal but
still their difference is not zero and an appriciable
voltage difference exist between the two ends which trigger
current and hence power to flow,
Is This Answer Correct ? | 4 Yes | 1 No |
Answer / akash kumar
actually for the transfer of active power in a ac transmission system you need phase difference between the Vs and Vr.a line loaded with its own surge impedance acts as of reactive nature only.its reactive power requirement is supplied by its own line capacitance.thus no reactive component of line current and hence highest ohmic current in the line!!!
P=(Vs*Vr/X)Sin(delta)
Is This Answer Correct ? | 2 Yes | 3 No |
Answer / muhammad ismail
Actually you are asking about Vs and Vr and PD.
On load side there is always ZERO Potential thats why power
flows to receiving side in line.
Is This Answer Correct ? | 0 Yes | 1 No |
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