The armature of shunt dc motor has 0.8ohm resistance and motor
is to run on 120V circuit.If motor is suddenly thrown on
circuit while armature at standstill then current drawn by
motor will be??Also back emf in normal running is 110V
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Answer / muhammad waqas
V =Eb + IaRa
Ra= 0.8ohm
Eb=110V
V=120V
Put values in eqn
120-110=0.8Ia
10/0.8= Ia
Ia = 12.5 A
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / shoaib
At stand still back emf Eb=0
Now
V=Eb + Ia Ra
120=0 + Ia(0.8)
Ia=120/0.8
Ia = 150amp
| Is This Answer Correct ? | 1 Yes | 0 No |
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