POLYMER ENGINEERING - QUESTION 24.2 : Let C% be the fractional crystallinity, Rs = density of sample, Ra = density of amorphous form and Rc = density of crystalline form. In a polymer, these unknowns could be related by the equation C% = (Rc / Rs) (Rs - Ra) / (Rc - Ra). (a) Find the equation of Rc as a function of C%, Rs and Ra. (b) Two samples of a polymer, C and D exist. For sample C, C% = 0.513 when Rs = 2.215 unit. For sample D, C% = 0.742 when Rs = 2.144 unit. Both samples C and D have the same values of Ra and Rc. Find the values of Ra and Rc in 6 decimal places.

1 Answers  

---

How can one quickly estimate the additional pressure drop to be introduced with more tube passes?

0 Answers  

---

i'm a chemical engineer with an aggregate of 80% and i'm going to attend for TCS next week...if i encounter a question like this how i have to answer... WHY YOU CHOOSE SOFTWARE RATHER THAN YOUR CORE COMPANIES?

0 Answers  

---

At what temperature does water have maximum density?

0 Answers  

---

NATURAL GAS ENGINEERING - QUESTION 26.1 : (a) In natural gas pipe sizing, the length of the pipe from the gas source metre to the farthest appliances is 60 feet. The maximum capacities for typical metallic pipes of 60 feet in length are : 66 cubic feet per hour for pipe size of 0.5 inches; 138 cubic feet per hour for pipe size of 0.75 inches; 260 cubic feet per hour for pipe size of 1 inch. By using the longest run method : (i) Find the best pipe size needed for the capacity of 75 cubic feet per hour. (ii) Estimate the suitable range of capacities for the pipe size of 1 inch. (b) The maximum capacities for typical metallic pipes of 50 feet in length are : 73 cubic feet per hour for pipe size of 0.5 inches; 151 cubic feet per hour for pipe size of 0.75 inches; 285 cubic feet per hour for pipe size of 1 inch. By using the branch method find the best pipe size needed for the capacity of 75 cubic feet per hour when the length of the pipe from the gas source metre to the appliance is 52 feet.

2 Answers  

---

AS PER IS(INDIAN STANDARD)RULES, IS INSTRUMENT EARTHING REQUIRE FOR INSRTUMENT WHICH IS ONLY 24V DC POWERED?

1 Answers  

---

can any one tell me that how shoul i prepere for entrance exams of psu i mean from which book i have to gone through?

3 Answers   BPCL Bharat Petroleum, GACL, GATE, IOCL,

---

what is the differance between Horizental and vertical heat exchanger?

11 Answers   Bihar Caustic and Chemicals,

---

Your favourite area of interest

7 Answers   Ambuja, CPCL, Genpact, Lilliput,

---

ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.16 : An engineer would like to invest his money in a home, business and bond. The implicit interest payment frequency is monthly for home loans, quarterly for business loans; semi annually for bonds. A generalized mathematical formula to calculate I = interest rate equivalence is I = (1 + i / N) ^ N - 1 where i = annual interest rate, N = number of payment per year. (a) Calculate the value of N for : (i) home loans; (ii) business loans; (iii) bonds. (b) For i = 0.08, find the value of I for : (i) home loans; (ii) business loans; (iii) bonds.

1 Answers  

---

ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.24 : (a) The net present value of an engineering project is given by V. Let Q = summation of [ T / (1 + I) ^ N ] from N = A to N = B, where P = project cost, T = tax inflow, N = duration. If V = P + Q where P = -$1000, T = $275, I = 0.12 (means 12 % , capital cost of project per year), A = 1 year, B = 5 years, calculate the value of V. (b) The present value tax shields are W = $ (11.9725, 9.1486, 6.5579, 4.1811, 2.0005) in 5 beginning balances of an engineering project. Find the adjusted present value of the engineering project X, when X = V + (summation of the values of W).

1 Answers  

---

How can you determine the proper pipe thickness for a slurry line?

0 Answers  

---