Answer / s. kotiyal

Sir u need 6 capacitor pannel
of 25 kvar.

Answer / rman

currently, the load is 0.75MVAR operating at 0.8pf. to enhance it to 0.95pf, the MVAR must be decreased to 0.329MVAR.
Q=0.75-0.329=0.36MVAR
0.36MVAR must be your operating reactive power. therefore your capacitance must be {0.36M/[0.36M/(415*0.95*sqrt(3))]^2*sqrt(3)} which will be your reactance at 0.0969 per phase. also to find the capacitor to be inserted per phase,assuming your frequency is 60Hz, C=(2*pi*60*0.0969)^(-1)
therefore the C=27.37mF

Answer / rsundareee

your original p.f is 0.8(Tan 0.8) and you required p.f is
0.95(Tan 0.95).Required p.f = kW(Tan0.8 - Tan 0.95),when
you select the breaker rating of Capacitor bank you have to
conside the Hormonics (33%),For exambe breaker rating will
be 100A it shall be (100+33=133) 160A MCCB.

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