Answer / abhishek singh

BECAUSE THE POWER OF EACH XMER IS EQUAL TO PRODUCT OF
CURENT AND VOLTAGE.SO P=VI SO WHEN VOLTAGE INCREASES THEN
CURRENT MUST BE DECREASE AND VICE VERSA.

Answer / vinod

CT are two type 1) Bar type & 2) wound type. In both case
secondary winding turns will be more, when current pass
thru the primary due to induction secondary will induced
voltage(prepotional to the ratio)will be very very high (ie
why CT should not be open circuited, cause insulation
failure and Ct damage)and reduce the quantity of current in
required preportion till the burden.
Remember the secondary current of CT is always preportional
to the primary current where as power TF is reverse.

Answer / ibrahim

power and frequency to be constant to make power constant v
increases automatically i decreases

Answer / vamshi kulkarni

simply to maintain V1I1=V2I2

Answer / jax

Question is wrong.

I have an existing old MCCB. ABB Model SACE, the rating are: Ue = 660 volts, Iu =1250 Amps, 3 poles, Ith (max) =800 amps at 45 deg C. I need a circuit breaker for my 3 phase motors, 380 volts 60 hz. the supplier required the minimum ampacity of the breaker to be 911 amps. can i use this breaker with rating of Iu =1250 amps but Ith = 800amps maximum?

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