Answer / v.purushotham

1. Grade of concrete M20 so ratio is 1:11/2:3
let volume of concrete - 1cum
total ratio- 1+1.5+3 = 5.5
cement = 1x1.54/5.5 = 0.28 cum so cement is =0.28x
1440Kg/cum = 403.2 Kg = 8.064 bags
sand-0.28*1.5= 0.42cum
aggregate- 2.8*3= 0.84 cum

2. plaster = suppose 12mm palster
consider 1 sqm ratio is 1:6
volume of concrete= .012x1= .012cum ( per 1sqm)
incrase 20% for joint, filling and wastage=.012*20%=.0144

calculate 1/3rd of mortar when
dry= .0144*1/3+.0144= .0192cum

summation of ratio = 7
cement= .0192/7=.00274cum
= .0789bags
sand= .00274*6=.0164cum

this formula applied for 6mm and 20mm also.
plaster area= paint area

Answer / padmarajan

M20 = 1:1.5:3
Volume = 1+1.5+3=5.5
Total volume ingredients for using =1.57
Volume of broken stone Require = (3/5.5) x 1.57 = 0.856 m3
Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3
Volume of cement = (1/5.5) x 1.57 = 0.285 m3
= 0.285 x1440 = 411 kg.

For 1m3 of M20 (1:1.5:3)
Broken stone = 0.856 m3
Sand = 0.472 m3
Cement = 8.22 bag

Answer / sjtbehera

1. Grade of concrete M20 so ratio is 1:11/2:3
let volume of concrete - 1cum
total ratio- 1+1.5+3 = 5.5
cement = 1x15.4/5.5 = 2.8 cum so cement is =2.8/.347=8 bags
sand-2.8*1.5= 4.2cum
aggregate- 2.8*3= 8.4 cum

2. plaster = suppose 12mm palster
consider 1 sqm ratio is 1:6
volume of concrete= .012x1= .012cum ( per 1sqm)
incrase 20% for joint, filling and wastage=.012*20%=.0144

calculate 1/3rd of mortar when
dry= .0144*1/3+.0144= .0192cum

summation of ratio=7 so cement= .0192/7=.00274cum
= .0789bags
sand= .00274*6=.0164cum

this formula applied for 6mm and 20mm also.
plaster area= paint area

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