Answer / susie

Answer :

Implementaion dependent

Explanation:

The char type may be signed or unsigned by default. If it is
signed then ch++ is executed after ch reaches 127 and
rotates back to -128. Thus ch is always smaller than 127.

main() { int i = 258; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

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main() { signed int bit=512, mBit; { mBit = ~bit; bit = bit & ~bit ; printf("%d %d", bit, mBit); } } a. 0, 0 b. 0, 513 c. 512, 0 d. 0, -513

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how to test pierrot divisor

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#define a 10 void foo() { #undef a #define a 50 } int main() { printf("%d..",a); foo(); printf("%d..",a); return 0; } explain the answer

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main() { int i =0;j=0; if(i && j++) printf("%d..%d",i++,j); printf("%d..%d,i,j); }

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main() { int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p } a. Runtime error. b. 1.00000 c. Compile error d. 0.00000

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