Answer / rk

d) it will print 0.0000.

If we typecast the result to float as shown below then
expected output will be printed(i.e. 1.0000)
printf("%f",(float) i/(*p) ); // i is divided by pointer p

Answer / guest

c) Error becoz i/(*p) is 25/25 i.e 1 which is int & printed
as a float,

So abnormal program termination,

runs if (float) i/(*p) -----> Type Casting

Answer / km

the answer to this question is implementation dependent:
if tried in Turbo C++
a) Runtime error
abnormal termination
if tried in Unix using GNU C
non of the above
you get a junk result

int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().

1 Answers  

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int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

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Is the following code legal? typedef struct a aType; struct a { int x; aType *b; };

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What are segment and offset addresses?

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