Answer / susie

Answer :

30,20,10

Explanation:

'{' introduces new block and thus new scope. In the
innermost block i is declared as,

const volatile unsigned

which is a valid declaration. i is assumed of type int. So
printf prints 30. In the next block, i has value 20 and so
printf prints 20. In the outermost block, i is declared as
extern, so no storage space is allocated for it. After
compilation is over the linker resolves it to global
variable i (since it is the only variable visible there). So
it prints i's value as 10.

main() { int i = 3; for (;i++=0;) printf(“%d”,i); }

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