Answer / raghuram.a

struct node
{
int data;
struct node *l;
struct node *r;
};
typedef struct node *n;
int oddnos(n root)
{
static int count;
n cur = root;
if(cur!=NULL)
{
if(cur->data%2==1)
count++;
oddnos(root->l);
oddnos(root->r);
}
return count;
}

What are the following notations of defining functions known as? i. int abc(int a,float b) { /* some code */ } ii. int abc(a,b) int a; float b; { /* some code*/ }

1 Answers  

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Find the largest number in a binary tree

7 Answers   Infosys,

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4. Main() { Int i=3,j=2,c=0,m; m=i&&j||c&I; printf(“%d%d%d%d”,I,j,c,m); }

2 Answers   Broadridge,

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main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

5 Answers   HCL,

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write a program to count the number the same (letter/character foreg: 's') in a given sentence.

2 Answers  

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Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

0 Answers  

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main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

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void func1(int (*a)[10]) { printf("Ok it works"); } void func2(int a[][10]) { printf("Will this work?"); } main() { int a[10][10]; func1(a); func2(a); } a. Ok it works b. Will this work? c. Ok it worksWill this work? d. None of the above

1 Answers   HCL,

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void main() { if(~0 == (unsigned int)-1) printf(“You can answer this if you know how values are represented in memory”); }

1 Answers  

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1 o 1 1 0 1 0 1 0 1 1 0 1 0 1 how to design this function format in c-language ?

2 Answers  

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main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

2 Answers   CSS, Wipro,

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main(){ unsigned int i; for(i=1;i>-2;i--) printf("c aptitude"); }

2 Answers  

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