main()
{
int i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}
Answer / susie
Answer :
0 0 1 3 1
Explanation :
Logical operations always give a result of 1 or
0 . And also the logical AND (&&) operator has higher
priority over the logical OR (||) operator. So the
expression ‘i++ && j++ && k++’ is executed first. The
result of this expression is 0 (-1 && -1 && 0 = 0). Now
the expression is 0 || 2 which evaluates to 1 (because OR
operator always gives 1 except for ‘0 || 0’ combination- for
which it gives 0). So the value of m is 1. The values of
other variables are also incremented by 1.
Is This Answer Correct ? | 39 Yes | 11 No |
PROG. TO PRODUCE 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1
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