Answer / susie

Answer :

0 0 1 3 1

Explanation :

Logical operations always give a result of 1 or
0 . And also the logical AND (&&) operator has higher
priority over the logical OR (||) operator. So the
expression ‘i++ && j++ && k++’ is executed first. The
result of this expression is 0 (-1 && -1 && 0 = 0). Now
the expression is 0 || 2 which evaluates to 1 (because OR
operator always gives 1 except for ‘0 || 0’ combination- for
which it gives 0). So the value of m is 1. The values of
other variables are also incremented by 1.

main() { char str1[] = {‘s’,’o’,’m’,’e’}; char str2[] = {‘s’,’o’,’m’,’e’,’\0’}; while (strcmp(str1,str2)) printf(“Strings are not equal\n”); }

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