#define square(x) x*x main() { int i; i = 64/squar

#define square(x) x*x

main()

{

int i;

i = 64/square(4);

printf("%d",i);

}

Question Posted / susie

4 Answers
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#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / susie

Answer :

64

Explanation:

the macro call square(4) will substituted by 4*4
so the expression becomes i = 64/4*4 . Since / and * has
equal priority the expression will be evaluated as (64/4)*4
i.e. 16*4 = 64

Is This Answer Correct ?

231 Yes

14 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / boby

Is This Answer Correct ?

20 Yes

1 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / mayur rangade

Is This Answer Correct ?

13 Yes

0 No

#define square(x) x*x main() { int i; i = 64/square(4); print..

Answer / manish

Is This Answer Correct ?

2 Yes

13 No

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