Answer / sameer

it because arrays index are pointers and you are giving
offsets from the base pointer & base pointer is starting
element address so it has offset zero from base pointer

Answer / surya.raj

Since I found this questions answer on a another website and
I can do copy and paste from there, but in order to make
copyright and royalty of original poster I am not tending to
do that so, here is the link below from where you can get
answer of your question.

http://developeronline.blogspot.com/2008/04/why-array-index-should-start-from-0.html

main() { extern out; printf("%d", out); } int out=100;

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write a program to count the number the same (letter/character foreg: 's') in a given sentence.

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Under linux environment can u please provide a c code for computing sum of series 1-2+3-4+5......n terms and -1+2-3+4-5...n terms..

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main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }

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There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

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#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }

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writte a c-programm to display smill paces

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

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What is the output for the program given below typedef enum errorType{warning, error, exception,}error; main() { error g1; g1=1; printf("%d",g1); }

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main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }

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void main () { int x = 10; printf ("x = %d, y = %d", x,--x++); } a. 10, 10 b. 10, 9 c. 10, 11 d. none of the above

2 Answers   HCL,

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main(int argc, char **argv) { printf("enter the character"); getchar(); sum(argv[1],argv[2]); } sum(num1,num2) int num1,num2; { return num1+num2; }

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