Answer / susie

Answer :

1 1

Explanation:

The integer value 257 is stored in the memory as, 00000001
00000001, so the individual bytes are taken by casting it to
char * and get printed.

main() { char not; not=!2; printf("%d",not); }

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How to count a sum, when the numbers are read from stdin and stored into a structure?

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main() { int i=3; switch(i) { default:printf("zero"); case 1: printf("one"); break; case 2:printf("two"); break; case 3: printf("three"); break; } }

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main() { printf("%d, %d", sizeof('c'), sizeof(100)); } a. 2, 2 b. 2, 100 c. 4, 100 d. 4, 4

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How do I write a program to print proper subset of given string . Eg :input: abc output:{},{a},{b},{c},{a,b},{a,c},{b,c}, {a,b,c}.I desperately need this program please mail me to saravana6m@gmail.com

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main() { int i=5; printf("%d",++i++); }

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main() { int i=10; void pascal f(int,int,int); f(i++,i++,i++); printf(" %d",i); } void pascal f(integer :i,integer:j,integer :k) { write(i,j,k); }

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how can i cast a char type array to an int type array

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#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

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1) int i=5; j=i++ + i++ + i++; printf("%d",j);This code gives the answer 15.But if we replace the value of the j then anser is different?why? 2)int i=5; printf("%d",i++ + i++ + i++); this givs 18.

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main() { printf("%d", out); } int out=100;

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program to find magic aquare using array

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