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A train travels a certain distance taking 7 hrs in forward
journey, during the return journey increased speed 12km/hr
takes the times 5 hrs.What is the distance traveled
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Answer / berend
420 km.
If v = speed on forward journey.
distance of forward journey = 7v
distance of return journey = 5(v+12) = 5v + 60
forward and return journey are equal so:
7v = 5v + 60
This means 2v = 60 and v = 30 km/hr.
The forward journey is 7*30 = 210 km.
The return journey is 5*42 = 210 km (not surprising).
Total distance traveled is 420 km.
| Is This Answer Correct ? | 78 Yes | 7 No |
Answer / piranjeet
the distance trvelled in forward journey is 210 km.it
would b same in returning.therefore total distance trvelled
is 420 km
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / dinesh
suppose speed=x
distance travel=speed*timetaken
so distance=7x
now return time
speed=x+12
timetaken=5
distance=5(x+12)
now solving this
7x=5(x+12)
x=30
so distance is 7*30=210
ans is 210;
| Is This Answer Correct ? | 8 Yes | 3 No |
Answer / premchand
for forward journey it travels 210km. same as in the case of
return journey. so 210+210= 420km is the correct answer.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / snehal
210 is correct ans
c if train travel same distance
consider P=7*X
WHERE x IS speed
p=5*(x+12)
by soving
v get 210
| Is This Answer Correct ? | 4 Yes | 2 No |
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