A train travels a certain distance taking 7 hrs in forward
journey, during the return journey increased speed 12km/hr
takes the times 5 hrs.What is the distance traveled
Answer
x=speed
y=distance
according to the first situation ,
x=y/7...(1)
according to second situation,
x+12=y/5
or
5(x+12)=y
5x+60=y.....(2)
by subtracting equation 1&2
x=30
:the train will travel 30km