Answer / v.ramakrishnan

In such circuits the frequency is internally divided by 12
to get 0.965MHz...(11.59/12=.965).

It is done so becoz the time required to fetch,decode &
execute instructions is about 1.0852 microseconds.Hence the
frequency would be 1/1.0852=0.924 MHz which is nearly equal
to 0.965 Mhz.

Answer / sachin

bcoz this crys osc is used as serial and as well as parallel
mode according to need in ckt.

Electronic technical analysis

1 Answers   Hella,

---

hi.i want to get cleared about ece and want to know what are the topics or chapters which were in 11 and 12 grade.esp., in maths and physics?ans me soon.i am fresher.

1 Answers  

---

What are the applications of cycloconverter?

1 Answers  

---

What is the gross data rate of GSM?

1 Answers  

---

What are the applications of am transceiver.

1 Answers  

---

I AM APPERING FOR RRB EXAM FOR SECTION ENGINEER I REQUEST U TO PLZ FORWORD THE PAPER PATTERN AND EVEN PREVIOUS QUESTION PAPER to stamil230@gmail.com

0 Answers   RRB,

---

what is the specialty of nand and nor gates?

1 Answers  

---

What are the advantages of parallel optical interface?

1 Answers  

---

With the help of diagram explain a cmos inverter.

1 Answers  

---

Define what is meant by fermi level in semiconductor? Where does the fermi level lie in an intrinsic semiconductor?

1 Answers  

---

what is E1 ? and how this is work,what is data rate of 1 one E1 and why?

1 Answers  

---

wat sud b the futher course after b.tech in this field........

1 Answers  

---