Answer / subhashish sen

I think the Question is wrong !!!!!The Question would have
been like this..

Why Function Overloading does not depend on the return type?

Ans : Function Overloading does not depend on the return
type but it depends on number, type and order of arguments
of function..

In this case Overloading Possible
-----------------------------------
Ex : int fun(int a,int b){}
int fun(int x,float y){}

In this case Overloading is not possible
---------------------------------------
int fun(int a,int b){}
float fun(int x,float y){}

The reason is..while invoking these function its not
necessary to get the return value always,means if you don't
get the return value it also works...But this wont be
possible for no,type or order of arguments..

If you need further clarification reply me....

Answer / manjunathtek

Function overloading has a return type...

Ex:
#include<iostream>
using namespace std;
//Function 1:

int max(int a, int b)
{
return (a>b)? a:b;
}

//Function 2:

float max(float a, float b)
{
return(a>b)? a:b;
}

int main()
{
int c;
float d;
c=max(5,4); //will display 5
cout<<c<<endl;
d=max(3.14,6.15); //will display 6.15
cout<<d<<endl;
return 0;
}

Important Concepts in Fn. Overloading:
a) Fun Overloading depends upon the type/number/order in
which the arguments are passed...
b) Fun Overloading can take place for a function which is
within the same scope... (i.e.) both function 1:, and
Function 2: should be in the same { ...} (both the
functions are within main() (i.e. same scope)...

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