A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?
Answers were Sorted based on User's Feedback
Answer / kl
|Is This Answer Correct ?||13 Yes||4 No|
Answer / teja
in both cases distance is same.
but we want total time means 10 min late
|Is This Answer Correct ?||17 Yes||9 No|
Answer / ramesh naidu
ans is:50 min....4/5th of his usual speed leads 10 min
late....means..1/5th of his speed equals
|Is This Answer Correct ?||11 Yes||4 No|
Answer / pradeep
We know speed × time = distance, so ((4/5)×s)×(t+10)=D
On solving above equation we get
4st+40s=5st. [ Since D=S×T]
|Is This Answer Correct ?||0 Yes||0 No|
Answer / deniro
speed is inversely proportional to time
|Is This Answer Correct ?||3 Yes||4 No|
Answer / rani t c
let a person's usual speed be x km/min
let the distance be d km
given (d/(4 x/5))-(d/x)=10
when we solve this equation we will get d=40 x
t=d/(4 x/5)=(40 x/(4 x/5))=(5*40)/4=50
answer is 50 min
|Is This Answer Correct ?||0 Yes||1 No|
Answer / kumar
|Is This Answer Correct ?||2 Yes||8 No|
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