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A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?
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Answer Posted / rani t c
let a person's usual speed be x km/min
let the distance be d km
given (d/(4 x/5))-(d/x)=10
when we solve this equation we will get d=40 x
t=?
t=d/(4 x/5)=(40 x/(4 x/5))=(5*40)/4=50
answer is 50 min
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