A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?
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Answer Posted / teja
Answer:50 min
explanation:
speed=distance/time
in both cases distance is same.
s1*t1=s2*t2
s*t=(4s/5)*(t+10)
t=40 min
but we want total time means 10 min late
40+10=50 min
| Is This Answer Correct ? | 29 Yes | 18 No |
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