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There are 5 burglars and once went to a bakery to rob it
obviously The first guy ate 1/2 of the total bread and 1/2
of the bread. The second guy ate 1/2 of the remaining and
1/2 of the bread. The third guy ,fourth guy and fifth guy
did the same. After fifth guy there is no bread left out.
How many bread are there?

Answers were Sorted based on User's Feedback



There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / swapna

The ans is 31.
Explaination: There are in total 31 breads.
1st person ate 15.5+ 0.5 bread
2nd person ate 7.5+0.5 bread
3rd person ate 3.5+0.5 bread
4th person ate 1.5+0.5 bread
5th person ate 0.5+0.5 bread

Is This Answer Correct ?    21 Yes 0 No

There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / guest

let the total no of breads be x.

1st man 2nd man
x- (x/2) - 1/2 - 1/2((x-1)/2) - 1/2 ..... so on.

ans is 31.

first ate : 15.5 + .5 = 16 remaining 15
second ate : 7.5+0.5 = 8 remaining 7.
third ate : 3.5 +0.5 = 4 remaining 3.
fourth ate : 1.5 + 0.5 = 2 remaining 1
fifth ate : 0.5 + 0.5 = 1 remaining 0

Is This Answer Correct ?    7 Yes 0 No

There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / vishal

3.5

Is This Answer Correct ?    0 Yes 5 No

There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / antony

8

Is This Answer Correct ?    0 Yes 5 No

There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / sabarish

65 .

Is This Answer Correct ?    0 Yes 6 No

There are 5 burglars and once went to a bakery to rob it obviously The first guy ate 1/2 of the to..

Answer / yln sagar

x= (x/2+1/2)+(x/4 +1/2)+(x/8+1/2)+(x/16+1/2)+(x/32+1/2)

hence
x=2.5+(31/32)x
(1/32)x=2.5
x=2.5*32
x=80

Is This Answer Correct ?    0 Yes 9 No

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